Answer :
The Lewis structure of each ion, we need to know the number of valence electrons present in each atom. For example, in the NO2- ion, nitrogen has 5 valence electrons while oxygen has 6 valence electrons. Thus, the total number of valence electrons is 5+2(6)=17.
We then place the least electronegative atom (nitrogen in this case) in the center, and connect the other atoms with single bonds. We then add electrons to satisfy the octet rule, placing them around each atom until we run out of electrons.
The Lewis structure for NO2- is:
O
||
N-O-
To determine the nitrogen-to-oxygen bond order, we count the number of bonds between nitrogen and oxygen and divide by the total number of bonds. In NO2-, there are two N-O bonds and one N=O bond. Thus, the nitrogen-to-oxygen bond order is (2/3) for the N-O bond and (1/3) for the N=O bond. This tells us that the N-O bonds are intermediate in strength between a single and a double bond.
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