High School

Dr. Howard is studying an endangered fox whose population is declining by 7.5% every year. If there are currently 2,913 foxes, how many will remain in 7 years?

Answer :

Final Answer:

In 7 years, there will be approximately 1,379 foxes remaining due to a 7.5% annual decline from the current population of 2,913 foxes. This decline reflects the ongoing threat to the endangered fox population.

Explanation:

To calculate the future fox population, we can use the formula for exponential decay:

[tex]N(t) =[/tex][tex]N_0[/tex] *[tex](1 - r)^t[/tex]

Where:

- N(t) is the future population.

- [tex]\(N_0\)[/tex] is the current population (2,913 foxes).

- r is the annual decline rate (7.5% or 0.075 as a decimal).

- t is the number of years (7 years in this case).

Plugging in these values:

N(7) = 2,913 * (1 - 0.075)⁷

Calculating this:

N(7) ≈ 1,379

So, in 7 years, there will be approximately 1,379 foxes remaining in the population.

This calculation shows the impact of a 7.5% annual decline on the fox population over time. It's essential to monitor and address such declines to protect endangered species like these foxes.

Learn more about current population

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Final answer:

Using the formula for exponential decay, approximately 1,498 foxes will remain in 7 years.

Explanation:

To find out how many foxes will remain in 7 years, we need to use exponential decay. The formula for exponential decay is A = P(1 - r)^t, where A is the final amount, P is the initial amount, r is the decay rate per time period (as a decimal), and t is the number of time periods. In this case, the initial amount of foxes is 2,913 and the decay rate is 7.5% or 0.075. We can plug in these values to the formula and calculate the final amount:

A = 2,913(1 - 0.075)^7

Simplifying the equation:

A ≈ 2,913(0.925)^7

A ≈ 2,913(0.514)

A ≈ 1,497.66

Therefore, approximately 1,498 foxes will remain in 7 years.

Learn more about Exponential Decay here:

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