Middle School

Dear beloved readers, welcome to our website! We hope your visit here brings you valuable insights and meaningful inspiration. Thank you for taking the time to stop by and explore the content we've prepared for you.
------------------------------------------------ Determine the specific heat of a material if a 35.9 g sample absorbed 96 J as it was heated from 293 K to 313 K.

Answer :

This is an incomplete question, here is a complete question.

Determine the specific heat of a material if a 35 g sample absorbed 96 J as it was heated from 293 K to 313 K.

Answer : The specific heat of a material is, 0.137 J/g.K

Explanation :

Formula used to calculate the specific heat of a material is:

[tex]q=m\times c\times (T_2-T_1)[/tex]

where,

q = heat absorbed = 96 J

m = mass of sample = 35 g

c = specific heat capacity of material = ?

[tex]T_1[/tex] = initial temperature = 293 K

[tex]T_2[/tex] = final temperature = 313 K

Now put all the given values in the above formula, we get:

[tex]96J=35g\times c\times (313-293)K[/tex]

[tex]c=0.137J/g.K[/tex]

Therefore, the specific heat of a material is, 0.137 J/g.K