Answer :
To solve this problem, we need to use the concept of moments and equilibrium from physics.
A see-saw balances when the moments (or turning forces) on either side of the fulcrum (the pivot point at the center) are equal.
The formula for the moment is:
[tex]\text{Moment} = \text{Force} \times \text{Distance from the fulcrum}[/tex]
Let's break down the problem step by step:
Identify Given Values:
- The see-saw is 800 cm long; therefore, it is supported at its center, so each side is 400 cm or 4 m long.
- The boy sits 1 m from the end of the see-saw, which means he is [tex]4 - 1 = 3[/tex] m from the fulcrum.
- The boy weighs 40 kgf.
- The man weighs 60000 gf, which can be converted to 60 kgf (since 1000 gf = 1 kgf).
Calculate the Moment for the Boy:
- Moment due to the boy [tex]= 40 \text{ kgf} \times 3 \text{ m} = 120 \text{ kgf\cdot m}[/tex].
Set Up the Equation for the Man's Position:
- Let [tex]x[/tex] be the distance the man should sit from the fulcrum to balance the see-saw.
- The moment due to the man [tex]= 60 \text{ kgf} \times x \text{ m}[/tex].
Equation for Balance:
For the see-saw to be in equilibrium (balanced), the moments must be equal:
[tex]60 \times x = 120[/tex]
Solving for [tex]x[/tex]:
[tex]x = \frac{120}{60} = 2 \text{ m}[/tex]
Conclusion:
- The man should sit 2 meters from the fulcrum to balance the see-saw.
By placing the man 2 meters from the center on the see-saw, the turning forces on either side are balanced, achieving equilibrium.