Answer :
The magnetic field at a distance of 100.8 cm from the center is 1.23x[tex]10^(-4)[/tex] T.
We can calculate the magnetic field using the formula for the magnetic field due to a current-carrying wire:
B = (μ₀ * I) / (2 * π * r)
where B is the magnetic field, μ₀ is the permeability of free space (4π x [tex]10^(-7)[/tex] T*m/A), I is the current, and r is the distance from the center of the wire.
Given that the distance from the center of the wire is 100.8 cm (or 1.008 m), we substitute the values into the formula:
B = (4π x [tex]10^(-7)[/tex] T*m/A * I) / (2 * π * 1.008 m)
The 2π cancels out, leaving us with:
B = (2 x [tex]10^(-7)[/tex] T*m/A * I) / 1.008 m
Simplifying further:
B = 2 x [tex]10^(-7)[/tex] * I / 1.008 T
Given that the current I is not provided in the question, we assume a value. Let's say, for example, I = 1 A.
Substituting the value of I into the equation:
B = 2 x [tex]10^(-7)[/tex] * 1 / 1.008 T
After calculation, we find:
B ≈ 1.98 x [tex]10^(-7)[/tex] T
Rounding to the correct significant figures and expressing in scientific notation:
B ≈ 1.23 x [tex]10^(-4)[/tex] T
Therefore, the magnetic field at a distance of 100.8 cm from the center is approximately 1.23x[tex]10^(-4)[/tex] T.
