Onyx Onyx
  • 24-03-2025
  • Chemistry
High School

Determine the amount of energy (heat) in Joules and Kcal required to raise the temperature of 98.5 grams of water from 37.0°C to 75.0°C.

Answer :

jeremiahkevinm jeremiahkevinm
  • 02-11-2024

Answer:

15660.712J

Explanation:

Q = m × c × del T

Q(energy) = ?

m (mass) = 98.5g

c = 4.184J

del T = 75-37 = 38 °C

Q = 98.5 × 4.184 × 38

Q = 15660.712 J

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