High School

Determine the absolute weight and the weight relative to the rotating Earth of a 94-kg man if he is standing on the surface of the Earth at a latitude of 38°.

Answers:
- Absolute weight (\(W_{\text{abs}}\)) = _____ N
- Relative weight (\(W_{\text{rel}}\)) = _____ N

Answer :

The 'absolute' weight of an object is the force it experiences due to gravity alone, while the 'relative' weight considers the centrifugal force due to the Earth's rotation, making the object seem lighter.

To calculate the absolute weight of an object, we use the formula W = m*g, where 'm' is the mass of the object and 'g' is the acceleration due to gravity. On Earth, the average value of 'g' is approximately 9.81 m/s^2.

So, for a 94-kg man:

Absolute Weight (W_abs) = m*g = 94 kg * 9.81 m/s^2 = 922.14 Newton (N)

However, because the Earth is rotating, the apparent weight of an object can be less than its absolute weight. This is due to the centrifugal force that acts outwards on rotating bodies. The difference is most significant at the equator and diminishes towards the poles.

The formula to calculate this relative weight or apparent weight on a rotating Earth is W_rel = m*(g - w^2*R*cos^2(latitude)), where 'w' is the angular velocity of Earth, 'R' is the Earth's radius, and 'latitude' is the latitude at which the person is located.

Unfortunately, I see in your question that you didn't provide values for the Earth's angular velocity or radius, so we can't compute the exact relative weight. However, the process would involve substituting the known values into the formula and calculating accordingly.

To know more about absolute weight, visit:

https://brainly.com/question/30155002

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