Answer :
To design a voltage divider circuit with an output voltage of 6V and a current of 60mA using a 12V battery, you can follow these steps:
1. Understand the voltage divider circuit: A voltage divider circuit is composed of two resistors in series. The output voltage is determined by the ratio of the resistances.
2. Determine the desired output voltage: In this case, the desired output voltage is 6V.
3. Calculate the resistance ratio: The resistance ratio is the ratio of the resistance connected to the output to the total resistance of the circuit. Since we know the output voltage and current, we can use Ohm's law (V = IR) to calculate the resistance connected to the output.
Resistance connected to the output (R2) = Output voltage (Vout) / Current (I)
R2 = 6V / 0.06A
R2 = 100Ω
4. Calculate the total resistance: The total resistance is the sum of the resistance connected to the output (R2) and the remaining resistance (R1) in the circuit. We can use the formula:
Total resistance (Rt) = R1 + R2
12V battery voltage (Vb) = Output voltage (Vout) + Voltage across R1 (V1)
V1 = Vb - Vout
V1 = 12V - 6V
V1 = 6V
Using Ohm's law, we can calculate the remaining resistance (R1):
R1 = V1 / I
R1 = 6V / 0.06A
R1 = 100Ω
5. Choose appropriate resistor values: Since we've calculated R1 and R2 to be 100Ω each, you can choose two resistors with a resistance value of 100Ω each.
6. Connect the circuit: Connect the 12V battery to the junction of the two resistors. Connect one end of the first resistor (R1) to the positive terminal of the battery, and connect the other end of R1 to one end of the second resistor (R2). Connect the other end of R2 to the negative terminal of the battery.
By following these steps and using resistors with a resistance of 100Ω each, you can design a voltage divider circuit that will provide an output voltage of 6V and a current of 60mA using a 12V battery.
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