High School

Convert the following temperatures to Celsius:

1. [tex]32^\circ F[/tex]

2. [tex]45^\circ F[/tex]

3. [tex]70^\circ F[/tex]

4. [tex]80^\circ F[/tex]

Answer :

Let's convert each given Fahrenheit temperature to Celsius using the formula for conversion:

[tex]\[ C = \frac{(F - 32) \times 5}{9} \][/tex]

1. Convert [tex]\( 32^\circ F \)[/tex] to Celsius:

[tex]\[ C = \frac{(32 - 32) \times 5}{9} \][/tex]
[tex]\[ C = \frac{0 \times 5}{9} \][/tex]
[tex]\[ C = 0.0^\circ C \][/tex]

2. Convert [tex]\( 45^\circ F \)[/tex] to Celsius:

[tex]\[ C = \frac{(45 - 32) \times 5}{9} \][/tex]
[tex]\[ C = \frac{13 \times 5}{9} \][/tex]
[tex]\[ C = 65/9 \][/tex]
[tex]\[ C = 7.22^\circ C \][/tex]

3. Convert [tex]\( 70^\circ F \)[/tex] to Celsius:

[tex]\[ C = \frac{(70 - 32) \times 5}{9} \][/tex]
[tex]\[ C = \frac{38 \times 5}{9} \][/tex]
[tex]\[ C = 190/9 \][/tex]
[tex]\[ C = 21.11^\circ C \][/tex]

4. Convert [tex]\( 80^\circ F \)[/tex] to Celsius:

[tex]\[ C = \frac{(80 - 32) \times 5}{9} \][/tex]
[tex]\[ C = \frac{48 \times 5}{9} \][/tex]
[tex]\[ C = 240/9 \][/tex]
[tex]\[ C = 26.67^\circ C \][/tex]

So, the conversions are:
- [tex]\( 32^\circ F \)[/tex] is [tex]\( 0.0^\circ C \)[/tex]
- [tex]\( 45^\circ F \)[/tex] is [tex]\( 7.22^\circ C \)[/tex]
- [tex]\( 70^\circ F \)[/tex] is [tex]\( 21.11^\circ C \)[/tex]
- [tex]\( 80^\circ F \)[/tex] is [tex]\( 26.67^\circ C \)[/tex]

Other Questions