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------------------------------------------------ Consider the numbers 34,258 and 47,163.

The value of 4 in 34,258 is [tex]$\quad$[/tex] times the value of 4 in 47,163.

To solve the given problem, we need to determine the value of the digit '4' in two different numbers and then compare these values.

The numbers given are 34,258 and 47,163.

1. Determine the value of 4 in 34,258:
- In the number 34,258, the digit '4' is in the thousands place.
- The value of a digit in the thousands place is calculated as the digit multiplied by 1,000.
- So, the value of 4 in 34,258 is [tex]$ 4 \times 1000 = 4000 $[/tex].

2. Determine the value of 4 in 47,163:
- In the number 47,163, the digit '4' is in the ten-thousands place.
- The value of a digit in the ten-thousands place is calculated as the digit multiplied by 10,000.
- So, the value of 4 in 47,163 is [tex]$ 4 \times 10000 = 40000 $[/tex].

3. Compare the values to find how many times one value is of the other:
- We need to find how many times the value of 4 in 47,163 is the value of 4 in 34,258.
- This comparison is made by dividing the larger value by the smaller value.
- Therefore, [tex]$ \frac{40000}{4000} = 10 $[/tex].

So, the value of 4 in 47,163 is 10 times the value of 4 in 34,258.