Consider the following code:

```java
for (int i = 12; i > 2; i -= 2) {
System.out.print(i + " ");
}
```

What is the output?

A. 12 10 8 6 4 2 0

B. 10 8 6 4 2

C. 10 8 6 4

D. 12 10 8 6 4 2

E. 12 10 8 6 4

Answer :

Final Answer:

The output is: 12 10 8 6 4 2.The code uses a for loop to print values of 'i' starting from 12, decreasing by 2 in each iteration until greater than 2. The loop stops before reaching 0 due to the loop condition.

Explanation:

The given code snippet is a for loop that iterates with the variable i starting from 12 and decrementing by 2 in each iteration until i is greater than 2. The loop body contains a print statement that outputs the value of i followed by a space.

In the first iteration, i is 12, so "12" is printed.

In the second iteration, i becomes 10, so "10" is printed.

This pattern continues, and the loop prints the values 8, 6, 4, and 2 in subsequent iterations.

When i becomes 0, the loop condition i > 2 is no longer true, and the loop terminates before reaching the value of i being negative. Therefore, the value 0 is not included in the output.

Hence, the final output is: 12 10 8 6 4 2.

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