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------------------------------------------------ Complete the synthetic division problem below:

[tex]\[ 2 \quad \longdiv \quad 1 \quad 5 \quad -1 \quad 4 \][/tex]

What is the quotient in polynomial form?

A. [tex]\(x - 5\)[/tex]
B. [tex]\(x + 5\)[/tex]
C. [tex]\(x + 7\)[/tex]
D. [tex]\(x - 7\)[/tex]

Answer :

To solve the synthetic division problem, we want to divide a polynomial by [tex]\( x - 2 \)[/tex] using synthetic division. The coefficients provided are from the polynomial [tex]\( 1x^3 + 5x^2 - 1x + 4 \)[/tex].

Here is a step-by-step guide on how to perform synthetic division:

1. Set Up the Synthetic Division:
- Write down the coefficients of the polynomial: [tex]\( 1, 5, -1, \)[/tex] and [tex]\( 4 \)[/tex].
- Place the divisor [tex]\( x - 2 \)[/tex] on the left. Since it's [tex]\( x - 2 \)[/tex], the number we use for division is [tex]\( 2 \)[/tex].

2. Bring Down the Leading Coefficient:
- Bring down the first coefficient, which is [tex]\( 1 \)[/tex].

3. Perform the Division:
- Multiply the number brought down (in this case, [tex]\( 1 \)[/tex]) by the divisor (which is [tex]\( 2 \)[/tex]), and place the result under the next coefficient.
- Add this result to the next coefficient:
- Multiply [tex]\( 1 \times 2 = 2 \)[/tex].
- Add this to the next coefficient: [tex]\( 5 + 2 = 7 \)[/tex].
- Repeat the process with this new value:
- Multiply [tex]\( 7 \times 2 = 14 \)[/tex].
- Add this to the next coefficient: [tex]\( -1 + 14 = 13 \)[/tex].
- Repeat one more time:
- Multiply [tex]\( 13 \times 2 = 26 \)[/tex].
- Add this to the last coefficient: [tex]\( 4 + 26 = 30 \)[/tex].

4. Interpret the Result:
- The numbers we have obtained represent the coefficients of the quotient and the remainder.
- So, the quotient coefficients are [tex]\( 1, 7, \)[/tex] and [tex]\( 13 \)[/tex], and the remainder is [tex]\( 30 \)[/tex].

5. Write the Quotient in Polynomial Form:
- Based on the quotient coefficients [tex]\( 1 \)[/tex] and [tex]\( 7 \)[/tex], the quotient polynomial is [tex]\( x^2 + 7x + 13 \)[/tex].

Since none of the provided options completely match what we calculated, it's possible there was an expectation for interpreting the calculation differently, or a potential error in options. However, based on resolving the coefficients for the synthetic division provided, we confirm the quotient polynomial derived from those steps.

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