Answer :
By setting up and solving a system of linear equations, we find that the cost of one square foot of grass sod is $9 and the cost of one bunch of ornamental grass is $10.
The problem presented is a classic example of a system of linear equations. We have two equations derived from the information provided:
Castel: 6s + 9o = $144
Huong: 9s + 7o = $151
Where s represents the cost per square foot of grass sod, and o represents the cost per bunch of ornamental grass. To solve for s and o, we can use a method like substitution or elimination.
Multiply the first equation by 3 and the second equation by 2 to eliminate o:
(3) 6s + 9o = 432
(2) 9s + 7o = 302
Now, we subtract the second resulting equation from the first:
18s + 27o = 432
18s + 14o = 302
After subtraction:
13o = 130
o = $10
We can then substitute the value of o into any of the original equations to find the cost of sod per square foot:
6s + 9(10) = $144
6s = $54
s = $9
Therefore, the cost of one ft' of grass sod is $9 and the cost of one bunch of ornamental grass is $10.
The cost of one ft' of grass sod is $9 and the cost of one bunch of ornamental grass is $10.
How to illustrate the information?
Based on the information, the appropriate equation will be:
6g + 9y = 144
9g + 7y = 151
where g = grass sod
o = ornamental grass
Multiply equation I by 9
Multiply equation ii by 6
54g + 81y = 1296
54g + 42y = 906
Subtract
39y = 390
y = 390/39
y = 10
From 9g + 7y = 151
9g + 7(10) = 151
9g = 151 - 70
9g = 81
g = 81/9
g = 9
Therefore, the cost of one ft' of grass sod is $9 and the cost of one bunch of ornamental grass is $10.
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