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------------------------------------------------ Calculate the specific heat capacity of a piece of wood if 1.50 kg of the wood absorbs 67,500 joules of heat, and its temperature changes from 32°C to 57°C.

Answer :

The specific heat capacity of the wood is calculated using the formula q = mcΔT, resulting in a value of 1,800 J/(kg°C).

To calculate the specific heat capacity of a piece of wood, we use the formula q = mcΔT, where 'q' is the heat energy absorbed, 'm' is the mass of the substance, 'c' is the specific heat capacity, and 'ΔT' is the change in temperature.

Given that 1.50kg of wood absorbs 67,500 joules of heat and the temperature change is from 32°C to 57°C, we have a temperature change of 25°C.

Plugging these values into the formula and solving for 'c':

  • 67,500 J = (1.50 kg) * c * (57°C - 32°C)
  • 67,500 J = (1.50 kg) * c * 25°C
  • c = 67,500 J / (1.50 kg * 25°C)
  • c = 67,500 J / (37.5 kg°C)
  • c = 1,800 J/(kg°C)

Thus, the specific heat capacity of the wood is 1,800 J/(kg°C), which is the final answer.