Answer :
The potential difference across the 6.00 µF capacitor is 3 volts.
Calculate the potential difference across the 6.00 µF capacitor.
To determine the potential difference across a capacitor, we use the formula:
Charge (Q) = Capacitance (C) × Voltage (V)
First, if we assume the charge on the capacitor is known, we can rearrange the formula to solve for voltage (V):
Voltage (V) = Charge (Q) / Capacitance (C)
If, for example, the charge (Q) stored on the 6.00 µF capacitor is 18 μC (microcoulombs), we can plug the values into the equation:
V = 18 µC / 6.00 µF
Converting units correctly and solving:
V = 3 V
Thus, the potential difference across the 6.00 µF capacitor is 3 volts.
