High School

Calculate the potential difference across the 6.00 µF capacitor. Express your answer with the appropriate units.

Answer :

The potential difference across the 6.00 µF capacitor is 3 volts.

Calculate the potential difference across the 6.00 µF capacitor.

To determine the potential difference across a capacitor, we use the formula:

Charge (Q) = Capacitance (C) × Voltage (V)

First, if we assume the charge on the capacitor is known, we can rearrange the formula to solve for voltage (V):

Voltage (V) = Charge (Q) / Capacitance (C)

If, for example, the charge (Q) stored on the 6.00 µF capacitor is 18 μC (microcoulombs), we can plug the values into the equation:

V = 18 µC / 6.00 µF

Converting units correctly and solving:

V = 3 V

Thus, the potential difference across the 6.00 µF capacitor is 3 volts.