Answer :
Answer:
The answer is: 18 moles and 1341, 72 grams of KCl
Explanation:
The molarity is defined as the moles of solute ( in this case KCl) in 1 liter of solution:
1L solution-----3 moles of KCl
6L solution-----x= (6L solutionx 3 moles of KCl)/1 L solution= 18 moles of KCl
We calculate the weight of 1 mol of KCl:
Weight 1 mol KCl= Weight K + Weight Cl= 39,09 g + 35, 45 g=74, 54 g/mol
1 mol KCl----- 74, 54 g
18 mol KCl----x= (18 mol KCl x 74, 54 g)/1 mol KCl=1341, 72 g
