Answer :
Final answer:
There are approximately 40.3 grams of magnesium in 97.4 grams of Mg(OH)2.
Explanation:
To calculate the number of grams of magnesium in Mg(OH)2, we first need to find the percent composition of magnesium in this compound, which is given as 41.7%. This means that in every 100 grams of Mg(OH)2, 41.7 grams are magnesium. To find the grams of magnesium in 97.4 grams of Mg(OH)2, you can set up a simple proportion:
(41.7 grams of Mg / 100 grams of Mg(OH)2) = (x grams of Mg / 97.4 grams of Mg(OH)2)
Cross-multiply and solve for x:
x = (41.7 grams / 100 grams) * 97.4 grams = 40.3 grams
So, there are approximately 40.3 grams of magnesium in 97.4 grams of Mg(OH)2.
Percent composition is a useful concept in chemistry to determine the relative amounts of different elements in a compound. It is essential for stoichiometry and chemical reactions.
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