High School

Calculate the moles of water produced from 1.57 mol [tex]O_2[/tex].

[tex]2H_2(g) + O_2(g) \rightarrow 2H_2O(g)[/tex]

Answer :

Final answer:

From the balanced chemical reaction, we can see that the molar ratio of oxygen to water is 1:2. Hence, 1.57 moles of oxygen would produce 3.14 moles of water in the reaction.

Explanation:

The subject of this question is stoichiometry in chemistry which involves understanding chemical equations and using them to solve problems like calculating the quantity of a product or reactant. In the given balanced chemical equation 2H₂(g) + O₂(g) → 2H₂O(g), we can notice that 1 mole of O₂ reacts with 2 moles of H₂ to produce 2 moles of H₂O. This means that the molar relationship between O₂ and H₂O is 1:2. So, if we have 1.57 moles of O₂ reacting, we will get a two-fold amount which is 3.14 moles of H₂O as the product.

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