Answer :
Answer:
666.93 kJ
Explanation:
Using the formula;
Q = m × c × ∆T
Where;
Q = amount of heat absorbed (Joules)
m = mass of substance (g)
c = specific heat capacity (4.184 J/g°C)
∆T = change in temperature (°C)
Based on the information provided in the question;
Q = ?
m = 2000g
∆T = 99.7 °C - 20 °C = 79.7 °C
c = 4.184 J/g°C
Using Q = m × c × ∆T
Q = 2000 × 4.184 × 79.7
Q = 666929.6 Joules
To calculate the amount of heat absorbed (Q) in kilojoules (kJ), we say;
1 joule = 0.001 kilojoule
666929.6 Joules = 666929.6 × 0.001
= 666.9296 KJ
Approximately, Q = 666.93 kJ.
Final answer:
To calculate the heat absorbed by water when heated from 20.0°C to 99.7°C, use the formula Q = m * c * ΔT, where Q is the heat absorbed, m is the mass, c is the specific heat, and ΔT is the temperature change.
Explanation:
To calculate the heat absorbed by water: Identify the key values: mass of water (2000 g), initial temperature (20.0°C), final temperature (99.7°C), and specific heat of water (4.184 J/g°C). Apply the formula: Q = m * c * ΔT, where Q is the heat absorbed, m is the mass, c is the specific heat, and ΔT is the temperature change. Substitute the values and calculate the heat absorbed in kJ.
