Answer :
The energy transferred by an appliance using mains electricity of 230V with a charge of 150C is 34.5 kJ.
Calculation of Energy Transferred by an Appliance
To calculate the energy transferred by an appliance using mains electricity, you can use the formula:
[tex]E = V * Q[/tex]
Where:
V is the voltage (230V in this case).
Q is the charge (150C here).
Plugging in the given values:
[tex]E = 230V * 150C = 34500J[/tex]
Since the question asks for the energy in kilojoules (kJ), we need to convert joules to kilojoules.
We know that [tex]1 kJ = 1000 J.[/tex]
So, [tex]34500 J = 34.5 kJ[/tex]
Therefore, the energy transferred by the appliance is 34.5 kJ.
Final answer:
The energy transferred by an electrical appliance using 230V with a charge of 150C is 34.5 kilojoules.
Explanation:
To calculate the energy transferred by an appliance using mains electricity, you would use the equation for calculating electrical energy. This is given by the formula E = V * Q, where E represents energy, V represents voltage and Q represents charge.
In this case, we are given a voltage V of 230 Volts and a charge Q of 150 Coulombs. To calculate the energy transferred, you multiply voltage and charge, which provides the energy in joules:
E = V * Q = 230V * 150C = 34500 Joules
However, we want the answer in kilojoules, (1kJ = 1000J), so we would need to convert this. By dividing by 1000, we get the energy as:
E = 34500J / 1000 = 34.5 kJ
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