Answer :
Final answer:
To find the ppm concentration of K+ ions in the given solution, calculate the mass of K+ ions based on the molecular weight of potassium sulphate and the mass of K in K2SO4, then apply the ppm formula using the mass of the solution.
Explanation:
To calculate the concentration in ppm of K+ ions in a solution prepared by dissolving 2.6 g of potassium sulphate (K2SO4) in 250 mL of solution, we must first determine the molecular weight of potassium sulphate and the mass of K+ ions in our sample.
Molecular weight of K2SO4 is:
2(K) + (S) + 4(O) = 2(38.1) + 32 + 4(16) = 174.2 g/mol
Next, we calculate the amount of K+ ions in the 2.6 g of K2SO4:
The ratio of the molecular weight of K to K2SO4 is 38.1/174.2.
Mass of K+ in our sample = 2.6 g × (2 × 38.1 / 174.2)
Since there are two K+ ions per molecule of K2SO4, you'll need to multiply this ratio by 2.
Finally, to calculate the ppm concentration:
ppm = (mass of K+ ions / mass of the solution) × 106
Assuming the density of the solution is approximately 1 g/mL, the mass of the solution is 250 mL × 1 g/mL = 250 g.
Substitute the mass of K+ ions and the mass of the solution into the formula.
