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------------------------------------------------ Calcium gluconate (C\(_{12}\)H\(_{22}\)CaO\(_{14}\), MWt=430) injection 10% is available in a 10 mL ampul. How many mEq of Ca\(^++\) does the ampul contain?

A. 2.33 mEq
B. 4.65 mEq
C. 232.56 mEq
D. 23.65 mEq

The amount of Calcium in a 10mL ampul of 10% Calcium gluconate solution is (B) 4.65 mEq. This is determined using the molecular weight of Calcium gluconate and the equivalency of Calcium ions (2 equivalents per mole)

Explanation:

To solve this question, we need to determine the number of milliequivalents (mEq) of Calcium present in the 10% Calcium gluconate injection. The molecular weight of calcium is 40.08 g/mol and since each calcium ion (Ca⁺⁺) has a valency of +2, it forms 2 equivalents per mole.

First, we need to determine the amount of calcium gluconate in the ampul. A 10% solution means 10g in every 100ml. Therefore, in a 10ml ampul, there is 1g of Calcium gluconate. Since the molecular weight of Calcium gluconate is 430 g/mol, this is equal to (1g/430 g/mol)=0.0023256 moles of Calcium gluconate.

Since each molecule of Calcium gluconate has one atom of Calcium, this is also the number of moles of Calcium in the ampul. Therefore, the number of milliequivalents is (0.0023256 moles x 2 equivalents/mole x 1000 milliequivalents/equivalent) = 4.651 mEq. So, the answer is B. 4.65 mEq.

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