Answer :
the braking distance increases by approximately 29.721 percent when the speed of the car increases by 13.9 percent.
Given: Speed of the car increases by 13.9 percent
Let v be the original velocity of the car.
When the speed increases by 13.9 percent, the new velocity becomes 1.139v.
Kinetic energy (KE) is directly proportional to the square of velocity.
Therefore, the kinetic energy of the car increases by [tex](1.139)^2[/tex] times or approximately 1.29721 times.
Braking distance is directly proportional to kinetic energy.
Hence, the braking distance increases by the same factor of 1.29721 times or approximately 29.721 percent.
So, the braking distance increases by approximately 29.721 percent when the speed of the car increases by 13.9 percent.
