Answer :
To find the probability that a 28-year-old will be alive in one year, we need to look at the data provided in the mortality table for age 28. The table indicates how many out of 100,000 people of a specific age are expected to be alive after one year.
For a 28-year-old, the table lists 99,873 expected to be alive out of 100,000 people. To determine the probability, you should follow these steps:
1. Identify the Number Expected to be Alive: Locate the row for age 28 in the table. You'll find that 99,873 people are expected to be alive out of 100,000.
2. Convert to Probability: Since there are 100,000 persons in total, you calculate the probability by dividing the number expected to be alive by the total population. Here's how:
[tex]\[
\text{Probability of being alive} = \frac{99,873}{100,000}
\][/tex]
3. Simplify the Fraction: This division results in a decimal representation of the probability:
[tex]\[
\text{Probability} = 0.99873
\][/tex]
Thus, the probability that a 28-year-old will be alive in one year is 0.99873 or 99.873%. This means that, statistically, about 99.873% of 28-year-olds are expected to survive through the year.
For a 28-year-old, the table lists 99,873 expected to be alive out of 100,000 people. To determine the probability, you should follow these steps:
1. Identify the Number Expected to be Alive: Locate the row for age 28 in the table. You'll find that 99,873 people are expected to be alive out of 100,000.
2. Convert to Probability: Since there are 100,000 persons in total, you calculate the probability by dividing the number expected to be alive by the total population. Here's how:
[tex]\[
\text{Probability of being alive} = \frac{99,873}{100,000}
\][/tex]
3. Simplify the Fraction: This division results in a decimal representation of the probability:
[tex]\[
\text{Probability} = 0.99873
\][/tex]
Thus, the probability that a 28-year-old will be alive in one year is 0.99873 or 99.873%. This means that, statistically, about 99.873% of 28-year-olds are expected to survive through the year.