Answer :
Atmospheric pressure is frequently measured in inches of mercury. Let's determine the pressure of the gas in various units based on the given atmospheric pressure of 28.75 inches of mercury.
1. To determine the pressure of the gas in millimeters of mercury (mmHg), we can use the conversion factor: 1 inch of mercury = 25.4 mm of mercury.
So, to convert 28.75 inches of mercury to millimeters of mercury, we multiply 28.75 by 25.4:
Pressure in mmHg = 28.75 inches of mercury * 25.4 mm of mercury/inch of mercury = 731.5 mmHg.
2. To determine the pressure of the gas in Torr, we can use the conversion factor: 1 Torr = 1 mmHg.
Since we already know the pressure in mmHg is 731.5, the pressure in Torr is also 731.5 Torr.
3. To determine the pressure of the gas in kilopascals (kPa), we can use the conversion factor: 1 inch of mercury = 3.38639 kPa.
Multiplying 28.75 inches of mercury by 3.38639 kPa/inch of mercury, we get:
Pressure in kPa = 28.75 inches of mercury * 3.38639 kPa/inch of mercury = 97.393 kPa.
4. To determine the pressure of the gas in atmospheres (atm), we can use the conversion factor: 1 atmosphere = 760 mmHg.
Dividing 731.5 mmHg by 760 mmHg/atmosphere, we get:
Pressure in atm = 731.5 mmHg / 760 mmHg/atmosphere = 0.9615 atm.
Therefore, the pressure of the gas is:
- 731.5 mmHg
- 731.5 Torr
- 97.393 kPa
- 0.9615 atm
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