High School

At the gym, Jasper was able to bench press 224 pounds, which was [tex]\frac{7}{8}[/tex] of the weight that Balin was able to bench press. Which shows the correct equation and value of [tex]x[/tex], the weight that Balin could bench press?

A. [tex]\frac{7}{8} x = 224[/tex]; [tex]x = 196[/tex] pounds
B. [tex]\frac{7}{8} x = 224[/tex]; [tex]x = 256[/tex] pounds
C. [tex]\frac{7}{8} = \frac{x}{224}[/tex]; [tex]x = 196[/tex] pounds
D. [tex]\frac{7}{8} = \frac{x}{224}[/tex]; [tex]x = 256[/tex] pounds

Answer :

To solve the problem of finding the weight that Balin could bench press, you should set up and solve the equation properly.

Let's start with the information given:

- Jasper was able to bench press 224 pounds.
- This weight, 224 pounds, is [tex]\(\frac{7}{8}\)[/tex] of what Balin could bench press.

We need to find Balin's bench press weight, which we'll call [tex]\(x\)[/tex]. Based on the problem, the equation to model this situation is:

[tex]\[
\frac{7}{8} \times x = 224
\][/tex]

To solve for [tex]\(x\)[/tex], we need to isolate it. We do this by dividing both sides of the equation by [tex]\(\frac{7}{8}\)[/tex], which is the same as multiplying by its reciprocal [tex]\(\frac{8}{7}\)[/tex]:

[tex]\[
x = 224 \times \frac{8}{7}
\][/tex]

Carrying out the multiplication gives us:

[tex]\[
x = 256
\][/tex]

Therefore, Balin was able to bench press 256 pounds. So, the correct equation and value of [tex]\(x\)[/tex] are:

[tex]\[
\frac{7}{8} x = 224 ; x = 256 \text{ pounds}
\][/tex]

The correct option is:

[tex]\(\frac{7}{8} x=224 ; x=256\)[/tex] pounds.