College

At the gym, Jasper was able to bench press 224 pounds, which was [tex]\frac{7}{8}[/tex] of the weight that Balin was able to bench press.

Which shows the correct equation and value of [tex]x[/tex], the weight that Balin could bench press?

A. [tex]\frac{7}{8}x = 224 ; x = 196[/tex] pounds
B. [tex]\frac{7}{8}x = 224 ; x = 256[/tex] pounds
C. [tex]\frac{7}{8} = \frac{x}{224} ; x = 196[/tex] pounds
D. [tex]\frac{7}{8} = \frac{x}{224} ; x = 256[/tex] pounds

Answer :

Sure! Let's solve the problem step-by-step:

Jasper was able to bench press 224 pounds, which is [tex]\(\frac{7}{8}\)[/tex] of the weight that Balin could bench press. We need to find how much weight Balin could bench press, which we'll call [tex]\(x\)[/tex].

1. Set up the equation based on the given information:

[tex]\[
\frac{7}{8}x = 224
\][/tex]

2. To find [tex]\(x\)[/tex], you need to isolate it on one side of the equation. You can do this by multiplying both sides of the equation by [tex]\(\frac{8}{7}\)[/tex], which is the reciprocal of [tex]\(\frac{7}{8}\)[/tex]:

[tex]\[
x = 224 \times \frac{8}{7}
\][/tex]

3. Calculate the value on the right side:

[tex]\[
x = 224 \times \frac{8}{7} = 256
\][/tex]

So, Balin could bench press 256 pounds.

Therefore, the correct equation and the value of [tex]\(x\)[/tex] are:

[tex]\(\frac{7}{8}x = 224 ; x = 256\)[/tex] pounds.