High School

At the gym, Jasper was able to bench press 224 pounds, which was [tex]\frac{7}{8}[/tex] of the weight that Balin was able to bench press. Which shows the correct equation and value of [tex]x[/tex], the weight that Balin could bench press?

A. [tex]\frac{7}{8} x = 224; \, x = 196[/tex] pounds
B. [tex]\frac{7}{8} x = 224; \, x = 256[/tex] pounds
C. [tex]\frac{7}{8} = \frac{x}{224}; \, x = 196[/tex] pounds
D. [tex]\frac{7}{8} = \frac{x}{224}; \, x = 256[/tex] pounds

Answer :

To solve this problem, we need to find the weight Balin could bench press. We know that Jasper was able to bench press 224 pounds, which was [tex]\(\frac{7}{8}\)[/tex] of the weight that Balin could bench press.

Let's represent the weight Balin could bench press as [tex]\(x\)[/tex].

The problem gives us the equation:

[tex]\[
\frac{7}{8}x = 224
\][/tex]

We need to solve for [tex]\(x\)[/tex], the weight Balin could bench press. To do this, we'll perform the following steps:

1. Isolate [tex]\(x\)[/tex]: To find [tex]\(x\)[/tex], we need to get rid of the fraction [tex]\(\frac{7}{8}\)[/tex]. We do this by multiplying both sides of the equation by the reciprocal of [tex]\(\frac{7}{8}\)[/tex], which is [tex]\(\frac{8}{7}\)[/tex].

[tex]\[
x = 224 \times \frac{8}{7}
\][/tex]

2. Calculate the Value of [tex]\(x\)[/tex]:

[tex]\[
x = \frac{224 \times 8}{7}
\][/tex]

[tex]\[
x = \frac{1792}{7}
\][/tex]

[tex]\[
x = 256
\][/tex]

So, the weight that Balin could bench press is 256 pounds.

The correct equation and value of [tex]\(x\)[/tex] is:
[tex]\[
\frac{7}{8}x = 224; \, x = 256 \, \text{pounds}
\][/tex]