College

At the gym, Jasper was able to bench press 224 pounds, which was [tex]\frac{7}{8}[/tex] of the weight that Balin was able to bench press. Which shows the correct equation and value of [tex]x[/tex], the weight that Balin could bench press?

A. [tex]\frac{7}{8}x = 224 ; x = 196[/tex] pounds
B. [tex]\frac{7}{8}x = 224 ; x = 256[/tex] pounds
C. [tex]\frac{7}{8} = \frac{x}{224} ; x = 196[/tex] pounds
D. [tex]\frac{7}{8} = \frac{x}{224} ; x = 256[/tex] pounds

Answer :

To solve this problem, we need to find out how much weight Balin could bench press. We know that Jasper's bench press weight is 224 pounds and that this is [tex]\(\frac{7}{8}\)[/tex] of Balin's weight.

Here’s how we can set up and solve this equation:

1. Set up the equation:
[tex]\[
\frac{7}{8} \times x = 224
\][/tex]
Here, [tex]\(x\)[/tex] represents the weight that Balin could bench press.

2. Solve for [tex]\(x\)[/tex]:
To find [tex]\(x\)[/tex], we need to isolate [tex]\(x\)[/tex] on one side of the equation. We can do this by multiplying both sides of the equation by the reciprocal of [tex]\(\frac{7}{8}\)[/tex], which is [tex]\(\frac{8}{7}\)[/tex].

[tex]\[
x = 224 \times \frac{8}{7}
\][/tex]

3. Calculate the result:
[tex]\[
x = \frac{224 \times 8}{7} = 256
\][/tex]

So, the correct equation and value for [tex]\(x\)[/tex], the weight that Balin could bench press, is [tex]\(\frac{7}{8}x = 224; x = 256\)[/tex] pounds.