High School

At the gym, Jasper was able to bench press 224 pounds, which was [tex]\frac{7}{8}[/tex] of the weight that Balin was able to bench press.

Which shows the correct equation and value of [tex]x[/tex], the weight that Balin could bench press?

A. [tex]\frac{7}{8} x = 224; \, x = 196[/tex] pounds
B. [tex]\frac{7}{8} x = 224; \, x = 256[/tex] pounds
C. [tex]\frac{7}{8} = \frac{x}{224}; \, x = 196[/tex] pounds
D. [tex]\frac{7}{8} = \frac{x}{224}; \, x = 256[/tex] pounds

Answer :

Sure! Let's solve the question step by step:

Jasper was able to bench press 224 pounds, which is [tex]\(\frac{7}{8}\)[/tex] of the weight Balin was able to bench press. We need to find the weight that Balin could bench press, which we'll call [tex]\(x\)[/tex].

The relationship can be expressed in the equation:
[tex]\[ \frac{7}{8} \cdot x = 224 \][/tex]

To solve for [tex]\(x\)[/tex], we need to get [tex]\(x\)[/tex] by itself. We can do this by multiplying both sides of the equation by the reciprocal of [tex]\(\frac{7}{8}\)[/tex], which is [tex]\(\frac{8}{7}\)[/tex]:

[tex]\[ x = 224 \times \frac{8}{7} \][/tex]

When you calculate that:
[tex]\[ x = 256 \][/tex]

Therefore, the correct equation and the value for [tex]\(x\)[/tex] is:
[tex]\[ \frac{7}{8} x = 224; \, x = 256 \, \text{pounds} \][/tex]

So, the correct choice is:
[tex]\[ \frac{7}{8} x = 224; \, x = 256 \, \text{pounds} \][/tex]