High School

Assuming that women's weights are normally distributed with a mean of [tex]\mu = 143[/tex] lb and a standard deviation of [tex]\sigma = 29[/tex] lb, find the following:

(Sketch first) [tex]P(114 \leq X \leq 172)[/tex]

Answer :

The probability P(114172) is approximately 0.1587, or 15.87%.

The probability of an event can be calculated by using the z-score formula and the standard normal distribution table. The z-score represents the number of standard deviations a data point is from the mean.

To find the probability P(114172), we need to convert it to a z-score.

The formula for calculating the z-score is:
z = (x - μ) / σ

Where:
x is the data point,
μ is the mean, and
σ is the standard deviation.

In this case, we have:
x = 114,
μ = 143, and
σ = 29.

Plugging these values into the formula, we get:
z = (114 - 143) / 29

Calculating this, we find that the z-score is approximately -0.999.

Now, we can use the standard normal distribution table or a calculator to find the probability associated with this z-score. The table or calculator will give us the probability of a z-score being less than -0.999.

Assuming a standard normal distribution, we can use a table to find that the probability P(z < -0.999) is approximately 0.1587.

Therefore, the probability P(114172) is approximately 0.1587, or 15.87%.

To learn more about probability here:

brainly.com/question/32117953#

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