Answer :
2a. Compression force ≈ 125.61 N
2b. Tension in each cord ≈ 150.74 N vertically and ≈ 125.61 N horizontally.
Given:
- Mass (m) = 20 kg
- Angle (θ) = 40 degrees
- Gravitational acceleration (g) = 9.81 m/s²
calculate the weight (W) of the mass:
W = m * g
W = 20 kg * 9.81 m/s² ≈ 196.2 N
1. The vertical component (W vertical) is W * cos(θ).
2. The horizontal component (W horizontal) is W * sin(θ).
1. W vertical = 196.2 N * cos(40°) ≈ 149.91 N
2. W horizontal = 196.2 N * sin(40°) ≈ 126.09 N
2a. The compression force in the massless strut is equal to the horizontal component of the weight, so it's approximately 126.09 N.
2b. The tension in each cord:
- Vertically, it balances the vertical component of the weight, so T vertical = W vertical ≈ 149.91 N.
- Horizontally, it balances the compression force in the strut, so T horizontal = Compression Force ≈ 126.09 N.
So, the tension in each cord is approximately 149.91 N vertically and 126.09 N horizontally.
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