Answer :
The weight of box 2 and box 3 is 33.72N and 15.32N
According to Lami's Theorem, if three forces acting at a point are in equilibrium, each force is proportional to the sine of the angle between the other two forces. The magnitudes of concurrent, coplanar, and non-collinear forces that keep an object in static equilibrium are all related to Lami's Theorem. This theorem also aids in the analysis of most mechanical and structural systems. For all three forces used in Lami's Theorem, the proportionality constant is the same.
Given box1 weighs 31N
Given two angles 63 and 24
So the third angle will be
180 – 87
= 93
By using Lamis theorem
T_2/(SIN 93)=T_3/(SIN (90+63))=T_1/(SIN (90+24))
Here T1 = 31N
Weight of box 2 = w2 = 31/cos24 x sin 93
= 33.72
Weight of box 3 = w3 = 31/cos24 x cos 63
= 15.32
Therefore the weight of box 2 and box 3 is 33.72N and 15.32N
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