Answer :
You begin eating the pizza if you want its temperature to be 135°F at 3:31:30 PM.
According to the Newton's law of cooling, the temperature of the pizza will decrease exponentially over time. This means that the temperature of the pizza at any given time can be modeled using the following equation:
T(t) = T_0 + (T_i - T_0) * e^(-kt)
where:
T(t) is the temperature of the pizza at time t
T_0 is the ambient temperature (73°F in this case)
T_i is the initial temperature of the pizza (425°F in this case)
k is the cooling constant
The cooling constant can be determined by using the following equation:
k = ln(T_i - T_0) / t
where:
t is the time it takes for the pizza to cool from T_i to T_0
In this case, we know that the pizza cools from 425°F to 300°F in 5 minutes. Therefore, we can calculate the cooling constant as follows:
k = ln(425 - 73) / 5
k = 0.1386
Now that we know the cooling constant, we can use the first equation to calculate the time it will take for the pizza to cool to 135°F.
135 = 73 + (425 - 73) * e^(-0.1386 * t)
t = ln(135 - 73) / -0.1386
t = 31.5 minutes
Therefore, you can begin eating the pizza at 3:31:30 PM.
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The following question may be like this:
A pizza baked at 425 ∘ F is removed from the oven at 3:00PM into a room that is a constant 73 ∘ F. After 5 minutes, the pizza is at 300 ∘F (a) At what time can you begin eating the pizza if you want its temperature to be 135∘F?
