Answer :
Final answer:
a. The negative sign indicates that the image is formed on the same side as the object, which means it is a real image. It is a magnified image formed by the converging lens. The height of the image will depend on the magnification factor.
b. the height of the image formed by the converging lens is approximately 2.59 cm.
Explanation:
a) To locate and describe the image formed by the converging lens, we can use the lens formula:
1/f = 1/v - 1/u
Where:
- f is the focal length of the lens
- v is the image distance from the lens
- u is the object distance from the lens
In this case, the object is placed 37.2 mm to the left of the lens, which is equivalent to -37.2 mm.
Substituting the given values into the lens formula:
1/35.9 mm = 1/v - 1/-37.2 mm
Simplifying the equation:
1/35.9 mm = (37.2 mm - v) / (v × -37.2 mm)
To find the location of the image, we can solve for v. By cross-multiplying and simplifying the equation, we get:
v = - (35.9 mm × -37.2 mm) / (37.2 mm - 35.9 mm)
v ≈ -38.4 mm
The negative sign indicates that the image is formed on the same side as the object, which means it is a real image.
Now, let's describe the image. Since the image is real and located on the same side as the object, it is a magnified image formed by the converging lens. The height of the image will depend on the magnification factor.
b) To find the height of the image, we can use the magnification formula:
m = -v/u
Where:
- m is the magnification
- v is the image distance from the lens
- u is the object distance from the lens
Substituting the given values:
m = -(-38.4 mm) / -37.2 mm
m ≈ 1.032
The positive magnification indicates an upright image. Since the magnification is greater than 1, the image is larger than the object.
To find the height of the image, we can multiply the height of the object by the magnification factor:
height of the image = magnification × height of the object
height of the image = 1.032 × 2.52 cm
height of the image ≈ 2.59 cm
Therefore, the height of the image formed by the converging lens is approximately 2.59 cm.
Learn more about converging lens here: https://brainly.com/question/15123066
#SPJ11
