Answer :
Final answer:
The height of the cliff is 35.8 meters.
Explanation:
The height of the cliff can be determined by using the equations of motion. Since the object is dropped and its initial velocity is zero, we can use the equation
[tex]h = (1/2)gt^2,[/tex]
where h is the height of the cliff, g is the acceleration due to gravity (9.8 m/s^2), and t is the time taken to hit the ground.
Substituting the given values (initial velocity = 0, final velocity = 26.5 m/s) into the equation for the time of flight of an object dropped from a height gives
[tex]h = (1/2)gt^2 = (1/2)(9.8 m/s^2)(2.711s)^2[/tex]
t = sqrt((2h)/g) = sqrt((2h)/9.8)
= 2.711s.
Solving for h gives us
= 35.8 m.
Therefore, the height of the cliff is 35.8 meters.
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