High School

An ice cream shop owner hires a clerk and informs him that the mean weight of scoops of ice cream should be 48 grams. The clerk weighs out seven ice cream scoops with the following weights in grams: 48, 46, 47, 43, 41, 50, and 49.

How many grams of ice cream should be added to the smallest of these scoops to obtain an average weight of 48 grams for the seven scoops?

Answer :

Final answer:

To obtain an average weight of 48 grams for the seven ice cream scoops, you should add 7 grams of ice cream to the smallest scoop.

Explanation:

To find the average weight of the seven ice cream scoops, we need to add up all the weights and divide the sum by 7. Let's calculate:

48 + 46 + 47 + 43 + 41 + 50 + 49 = 324

Now, we divide the sum by 7 to find the average:

324 ÷ 7 = 46.29

The average weight of the seven scoops is approximately 46.29 grams.

To obtain an average weight of 48 grams for the seven scoops, we need to add enough ice cream to the smallest scoop to make its weight equal to 48 grams. The smallest scoop currently weighs 41 grams, so we need to add:

48 - 41 = 7 grams

Therefore, we should add 7 grams of ice cream to the smallest scoop to obtain an average weight of 48 grams for the seven scoops.

Learn more about calculating the average weight of ice cream scoops here:

https://brainly.com/question/22411905

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