High School

Penny's solving work is shown here. Has she solved this equation correctly?

1. [tex]\(\begin{aligned} \frac{3}{5} y - 8 & = 4 \\ +8 & +8 \end{aligned}\)[/tex]

2. [tex]\(\frac{5}{3} \cdot \frac{3}{5} y = 12 \cdot \frac{5}{3}\)[/tex]

3. [tex]\(\begin{array}{l} y = \frac{60}{3} \\ y = 20 \end{array}\)[/tex]

Options:

A. Yes, Penny's work is correct, and 20 is the correct solution.

B. No, Penny is wrong. She should have multiplied both sides by [tex]\(\frac{5}{3}\)[/tex] BEFORE adding 8 to both sides.

C. No, Penny is wrong. In line 2, she should have multiplied both sides by [tex]\(\frac{-5}{3}\)[/tex].

D. No, Penny is wrong. In line 1, she should have SUBTRACTED 8.

Answer :

Certainly! Let's go through Penny's work step-by-step to see if she solved the equation correctly.

The original equation given is:
[tex]\[
\frac{3}{5} y - 8 = 4
\][/tex]

Step 1: Add 8 to both sides

To isolate the term with [tex]\(y\)[/tex], we first add 8 to both sides of the equation:

[tex]\[
\frac{3}{5} y - 8 + 8 = 4 + 8
\][/tex]

Simplifying both sides gives:

[tex]\[
\frac{3}{5} y = 12
\][/tex]

Step 2: Multiply both sides by [tex]\(\frac{5}{3}\)[/tex]

To solve for [tex]\(y\)[/tex], we need to get rid of the fraction [tex]\(\frac{3}{5}\)[/tex] that is multiplying [tex]\(y\)[/tex]. We can do this by multiplying both sides of the equation by the reciprocal, which is [tex]\(\frac{5}{3}\)[/tex]:

[tex]\[
\left(\frac{5}{3}\right) \cdot \frac{3}{5} y = 12 \cdot \frac{5}{3}
\][/tex]

On the left side, the [tex]\(\frac{5}{3} \cdot \frac{3}{5}\)[/tex] simplifies to 1, leaving:

[tex]\[
y = 12 \cdot \frac{5}{3}
\][/tex]

Step 3: Calculate the value of [tex]\(y\)[/tex]

Now, we simplify the right side:

[tex]\[
y = \frac{12 \times 5}{3} = \frac{60}{3} = 20
\][/tex]

Therefore, [tex]\(y = 20\)[/tex].

Conclusion:

Penny's calculations are correct, and the solution to the equation is indeed [tex]\(y = 20\)[/tex]. Thus, she solved the equation correctly.