High School

An empty 3.00 L bottle weighs 1.70 kg. Filled with a certain wine, it weighs 4.72 kg. The wine contains 11.5% ethyl alcohol, [tex]C_2H_6O[/tex], by mass. How many grams of ethyl alcohol are there in 250.0 mL of this wine?

Answer :

28.94 g of alcohol.

First, calculate the mass of 3.00 l of wine.
4.72 kg = 1.70 kg = 3.02 kg

Now calculate the mass of 250.0 ml of the wine. Using ratios will work for this
(3020 g)/(3000 ml) = (X g)/(250 ml)

Multiply both sides by 250 ml
(3020 g * 250 ml) / (3000 ml) = X
(755000 ml g) / (3000 ml) = X
251.667 g = X

So 250.0 ml of wine has a mass of 251.667 g
Now multiply by 0.115 to get the mass of alcohol
251.667 g * 0.115 = 28.94 g

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