Answer :
The yearly cost to operate the 100-W driveway light bulb, if it is used every day for a 365-day year, is approximately $36.50.
1. Determine the energy consumption per day:
The bulb uses 100 watts of power and is on for 10 hours each day. Therefore, the daily energy consumption is:
[tex]\[ 100 \text{ W} \times 10 \text{ hours} = 1000 \text{ Wh/day} \][/tex]
2. Convert the daily energy consumption to kilowatt-hours:
Since there are 1000 watts in a kilowatt, we convert the daily energy consumption to kilowatt-hours (kWh):
[tex]\[ 1000 \text{ Wh/day} \div 1000 = 1 \text{ kWh/day} \][/tex]
3. Calculate the yearly energy consumption:
The bulb is used every day for a year, so the yearly energy consumption is:
[tex]\[ 1 \text{ kWh/day} \times 365 \text{ days/year} = 365 \text{ kWh/year} \][/tex]
4. Determine the cost per kilowatt-hour:
The power company charges 10¢ per kWh, which is equivalent to $0.10 per kWh.
5. Calculate the yearly cost:
Multiply the yearly energy consumption by the cost per kWh to find the yearly cost:
[tex]\[ 365 \text{ kWh/year} \times \$0.10/\text{kWh} = \$36.50/\text{year} \][/tex]
Therefore, the yearly cost to operate the bulb is approximately $36.50.
Answer:
36.50$
Step-by-step explanation:
The power of the light bulb in this problem is
P = 100 W = 0.1 kW
And the light bulb is operated for a time of
t = 10 hours
per day.
The light bulb is operated over 1 year (365 days), so the number of hours of operation is:
[tex]T=t\cdot 365 = 10 \cdot 365 =3650 h[/tex]
So the total energy consumed by the light bulb is
[tex]E=PT=(0.1 kW)(3650 h)=365 kWh[/tex]
We know that the cost of operation is
p = 10 cents/kWh
Therefore, the total cost will be:
[tex]c=E\cdot p =(365)(10)=3650 c[/tex]
So, 3650 cents, or 36.50$.
