High School

An electric car is designed to run off a bank of 12.0-V batteries with a total energy storage of [tex]2.00 \times 10^7 \text{ J}[/tex].

(a) If the electric motor draws [tex]8.00 \text{ kW}[/tex], what is the current delivered to the motor?

A. 0.67 A
B. 1.33 A
C. 4.00 A
D. 8.00 A

Answer :

Final answer:

The current delivered to the motor is calculated using the power equation P = IV. With a motor drawing 8.00 kW and a voltage of 12.0 V, the current is found to be approximately 667 A.

Explanation:

To calculate the current delivered to the electric motor by the 12.0-V batteries when the electric motor draws 8.00 kW, we can use the power equation P = IV, where P is power in watts (W), I is current in amperes (A), and V is voltage in volts (V).

First, we rearrange the equation to solve for current (I): I = P/V. Then, we can plug in the values for power (P = 8.00 kW) and voltage (V = 12.0 V). It is important to convert 8.00 kW to watts by multiplying by 1,000, getting 8,000 W.

I = 8,000 W / 12.0 V = 666.67 A

Therefore, the current delivered to the motor is 666.67 A, which can be approximated to 667 A (Option C).