Answer :
Final answer:
The current delivered to the motor is calculated using the power equation P = IV. With a motor drawing 8.00 kW and a voltage of 12.0 V, the current is found to be approximately 667 A.
Explanation:
To calculate the current delivered to the electric motor by the 12.0-V batteries when the electric motor draws 8.00 kW, we can use the power equation P = IV, where P is power in watts (W), I is current in amperes (A), and V is voltage in volts (V).
First, we rearrange the equation to solve for current (I): I = P/V. Then, we can plug in the values for power (P = 8.00 kW) and voltage (V = 12.0 V). It is important to convert 8.00 kW to watts by multiplying by 1,000, getting 8,000 W.
I = 8,000 W / 12.0 V = 666.67 A
Therefore, the current delivered to the motor is 666.67 A, which can be approximated to 667 A (Option C).