An aluminum object with a mass of 3.88 kg and at a temperature of 21.6 °C comes into thermal contact with an 8.06 kg copper object initially at a temperature of 97.9 °C. What will be the equilibrium temperature of the two objects? Neglect heat transfer between the objects and the environment. The specific heats are [tex]c_{al} = 900 \, \text{J/kg°C}[/tex] and [tex]c_{cu} = 387 \, \text{J/kg°C}[/tex].

The equilibrium temperature of an aluminium and copper object when brought into thermal contact is found using the conservation of energy principle, with specific heat values provided for each metal.

Explanation:

The question involves finding the equilibrium temperature when an aluminium object and a copper object come to thermal contact. To solve this, we can use the principle of conservation of energy where the heat lost by the copper object will equal the heat gained by the aluminium object. The formula to calculate this is:

Qlost = Qgained

For copper (losing heat): Qcu = mcu · ccu · (∂Tcu)

For aluminium (gaining heat): Qal = mal · cal · (∂Tal)

We can set these equal to each other and solve for the final temperature (Tfinal). The specific heat (c) for each metal is given: Aluminium (c_al) is 900 J/kg°C and Copper (c_cu) is 387 J/kg°C. By equating the heat lost by copper to the heat gained by aluminium, we can find the equilibrium temperature. We assume no heat is lost to the environment. The solution involves setting up the equation, substituting the values, and then solving for the final temperature.