An airplane is flying at an elevation of 1500 feet. What is the airplane's angle of elevation from the runway when it is 5000 feet from the runway? Round to the nearest tenth.

Question

High School

Answer :

jocelynarlete01 jocelynarlete01 · Answer 1 · 2024-08-01T19:30:48-04:00

Answer 16.7 degrees
Opp/ adj= tan A; A tan inverse
(1500/5000) A=16.7 degrees

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saimaparvezVT saimaparvezVT · Answer 2 · 2025-05-31T00:51:48-04:00

The angle of elevation from the runway to the airplane is 16.7 degrees.

A right triangle is defined as a triangle in which one angle is a right angle or two sides are perpendicular.

To determine the angle of elevation from the runway, we need to use some trigonometry.

Let's represent the angle of elevation from the runway to the airplane "x". We can set up the following right triangle:

We can use the tangent function to find the angle "x":

tan(x) = opposite/adjacent

tan(x) = 1500/5000

tan(x) = 3/10

We can use a calculator or a table of tangents to find the angle "x" in degrees. The angle "x" is approximately 16.6992 degrees.

Rounded to the nearest tenth, the angle of elevation from the runway to the airplane is 16.7 degrees.

Learn more about the right triangle here:

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