Answer :
The pilot was flying at a height of 490 meters.
To determine the height at which the pilot was flying, we can use the equation of motion for vertical motion. The formula is given by:
h = ut + (1/2)gt²
Where h is the height, u is the initial vertical velocity, g is the acceleration due to gravity, and t is the time.
The initial vertical velocity is 0 m/s since the pilot is flying horizontally.
The acceleration due to gravity is 9.8 m/s²
The time is 10 seconds since the bomb hits the target after 10 seconds.
Plugging the values into the formula, we get:
h = 0 + (1/2) * 9.8 * (10)²
h = 0 + 4.9 * 100
h = 490 meters
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