Answer :
Final answer:
On the Stanford-Binet test, an 8-year-old scoring the same as an average 10-year-old would have an IQ of 125.
Explanation:
The Stanford-Binet test measures intelligence, with the average intelligence quotient (IQ) being set at 100. An 8-year-old scoring the same as a typical 10-year-old would therefore have performed above the average for their age group. The ratio used in the original Stanford-Binet was the mental age (MA) divided by the chronological age (CA), multiplied by 100. Therefore, if an 8-year-old has the mental age of an average 10-year-old, then his/her IQ would be (10/8)*100 = 125. So, this child was said to have an IQ of 125.
Learn more about Stanford-Binet IQ score here:
https://brainly.com/question/28205198
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