Answer :
Final Answer:
According to the given question,
(a) The molality of a solution created with 36.9 g of C₆H₁₂O₆ dissolved in 482 g of water to make 500. mL of solution is approximately 0.426 mol/kg.
(b) The molarity of a solution created with 35.2 g of C₆H₁₂O₆ dissolved in 482 g of water to make 555 mL of solution is approximately 0.351 M.
Explanation:
a) First, calculate the moles of C₆H₁₂O₆ (glucose) for the molality:
Calculate moles of glucose (C₆H₁₂O₆):
Molar mass of C₆H₁₂O₆= 6(12.01 g/mol) + 12(1.01 g/mol) + 6(16.00 g/mol) = 180.18 g/mol
For molality (m):
we have the following formula for the Molality (m):
[tex]\[ m = \frac{\text{moles of solute}}{\text{mass of solvent (in kg)}} \][/tex]
Moles of C₆H₁₂O₆ = \(\frac{36.9 g}{180.18 g/mol} = 0.205 mol\)
Mass of water (solvent) = 482 g = 0.482 kg
Molality (m) = \(\frac{0.205 mol}{0.482 kg} = 0.426 mol/kg\)
So, The molality (m) of the solution is approximately 0.426 mol/kg.
b) First, calculate the moles of C₆H₁₂O₆ (glucose) for the molarity:
Molar mass of C₆H₁₂O₆= 6(12.01 g/mol) + 12(1.01 g/mol) + 6(16.00 g/mol) = 180.18 g/mol
we have the following formula for the Molarity (M):
[tex]\[ M = \frac{\text{moles of solute}}{\text{volume of solution (in L)}} \][/tex]
Moles of C₆H₁₂O₆ = [tex]\(\frac{35.2 g}{180.18 g/mol} = 0.195 mol\)[/tex]
Volume of solution = 555 mL = 0.555 L
Molarity (M) = [tex]\(\frac{0.195 mol}{0.555 L} = 0.351 M\)[/tex]
So, The molarity (M) of the solution is approximately 0.351 M.
To learn more about the Molality, click here.
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