Answer :
Final answer:
Using Newton's Second Law, the net force acting on the acrobat is calculated to be 110 N. The acrobat's upward acceleration, with a mass of 60 kg, can be determined to be approximately 1.83 m/s².
Explanation:
The question asks about the upward acceleration of an acrobat hanging from a trapeze. The acrobat, with a mass of 60 kg, applies a force of 588 N to the trapeze bar. The two ropes providing the upward forces contribute 349 N each. This results in a net force that can be calculated by subtracting the downward force from the total upward force, using Newton's Second Law, F = ma.
First, let's add up the forces - the total upward force is 2 * 349 N = 698 N. The downward force (weight of the acrobat) is 588 N. The net force is thus 698 N - 588 N = 110 N. Now, using Newton's Second Law, which states that force equals mass times acceleration, we can rearrange the formula to solve for acceleration (a), resulting in - a = F / m. If we plug in our values, we get a = 110 N / 60 kg, which equals approximately 1.83 m/s² upward.
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The upward acceleration of the acrobat is 5.82 m/s².
Acceleration is the rate of change of the velocity of an item with appreciation to time. Accelerations are vector portions. The orientation of an item's acceleration is given by the orientation of the net pressure appearing on that object.
Calculation:-
downward force = 588 N
upward tension force = 588 N
Extra upward force = 349 N
acceleration = net force/total mass
= 349 / 60
= 5.82 m/s²
Acceleration is the charge at which velocity modifications with time, in terms of each speed and route. A factor or an object moving in a straight line is accelerated if it quickens or slows down. movement on a circle is extended despite the fact that the rate is consistent because the course is continually changing.
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