Answer :
The horizontal force on M2 due to its attachment to My is calculated by considering the masses of My and M2 and the forward acceleration of the system. Using Newton's second law, the force exerted by T on My and the force exerted by My on M2 are calculated separately. The force exerted by My on M2 is found to be 96.8 N.
To determine the horizontal force on M2 due to its attachment to My, we can use Newton's second law of motion, which states that the force acting on an object is equal to the mass of the object multiplied by its acceleration. In this case, we need to consider the acceleration of the system and the masses of My and M2.
Given:
Mass of T (tractor) = 208 kg
Mass of My = 139 kg
Mass of M2 = 121 kg
Forward acceleration (a) = 0.8 m/s²
To find the horizontal force on M2, we need to consider the net force acting on M2. This net force is the sum of the force exerted by T on My and the force exerted by My on M2.
Using Newton's second law, we can calculate the force exerted by T on My:
Force on My ([tex]F_m_y[/tex]) = Mass of My ([tex]M_m_y[/tex]) * Acceleration (a)
[tex]F_m_y[/tex] = 139 kg * 0.8 m/s²
[tex]F_m_y[/tex] = 111.2 N
Similarly, we can calculate the force exerted by My on M2:
Force on M2 ([tex]F_m_2[/tex]) = Mass of M2 ([tex]M_m_2[/tex]) * Acceleration (a)
[tex]F_m_2[/tex] = 121 kg * 0.8 m/s²
[tex]F_m_2[/tex]= 96.8 N
Therefore, the horizontal force on M2 due to its attachment to My is 96.8 N.
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