Answer :
The dimensions x and y that minimize the cost of construction is 22.3 ft x 89.9 ft
How to find the Dimensions that minimize the cost of construction
Let the width and length be x and y respectively.
We are given area as 2000 Sq.ft.
Thus;
xy = 2000 - - - (eq 1)
We are told that the brick wall costs $10 per linear foot and the chain link costs $5 per linear foot. Thus;
C(x) = 10x + 5y
From eq(1),y = 2000/x
Thus;
C(x) = 20x + 5(2000/x)
C(x) = 20x + 10000/x
To minimize this, we will differentiate and equate to 0.
Thus;
C'(x) = 20 - 10000/x²
Equating to zero;
20 - 10000/x² = 0
20 = 10000/x²
20x² = 10000
Divide both sides by 20;
x² = 8000/20
x² = 500
x = √500
x = 22.3 ft
Putting 22.3 for x in eq 1,we have;
20y = 2000
y = 2000/22.3
y = 89.9 ft
Learn more about Dimensions at:https://brainly.com/question/26740257
#SPJ1