Answer :
Final answer:
The pressure inside two soap bubbles is 3 atmosphere and 114 cm of hg. The ratio of their respective volumes is 1:20. None of the option provided is the answer.
Explanation:
I'd be glad to help you determine the ratio of the volumes of the two soap bubbles.
Given:
- Pressure inside soap bubble 1: 3 atm
- Pressure inside soap bubble 2: 114 cm of Hg
Steps:
Convert the pressure of bubble 2 to atm:
1 atm = 760 cm Hg
Therefore, 114 cm Hg * (1 atm / 760 cm Hg) = 0.15 atm (rounded to two decimal places)
Apply the relationship between pressure and volume for soap bubbles:
For soap bubbles at constant temperature, pressure and volume are inversely proportional. This principle is known as Boyle's Law:
p1 * V1 = p2 * V2
where:
- p1 and p2 are the pressures
- V1 and V2 are the volumes
Solve for the ratio of volumes (V1/V2):
Since we're looking for the ratio V1/V2, we can arrange the equation as:
V1/V2 = p2 / p1
Plug in the values:
V1/V2 = 0.15 atm / 3 atm
V1/V2 = 0.05
Therefore, the ratio of the volumes of the two soap bubbles is 1:20. This means that soap bubble 2 has a volume 20 times larger than soap bubble 1.
Correct answer: 1:20 (none of the option is the answer)
